ref_remove_duplicates(): simplify loop logic

Change the loop body into the more straightforward

* remove item from the front of the old list
* if necessary, add it to the tail of the new list

and return a pointer to the new list (even though it is currently
always the same as the input argument, because the first element in
the list is currently never deleted).

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 6 insertions, 2 deletions

diff --git a/remote.h b/remote.h
index 131130a611..c07eb9950a 100644
--- a/remote.h
+++ b/remote.h
@@ -149,9 +149,13 @@ int resolve_remote_symref(struct ref *ref, struct ref *list);
 int ref_newer(const unsigned char *new_sha1, const unsigned char *old_sha1);
 
 /*
- * Removes and frees any duplicate refs in the map.
+ * Remove and free all but the first of any entries in the input list
+ * that map the same remote reference to the same local reference.  If
+ * there are two entries that map different remote references to the
+ * same local reference, emit an error message and die.  Return a
+ * pointer to the head of the resulting list.
  */
-void ref_remove_duplicates(struct ref *ref_map);
+struct ref *ref_remove_duplicates(struct ref *ref_map);
 
 int valid_fetch_refspec(const char *refspec);
 struct refspec *parse_fetch_refspec(int nr_refspec, const char **refspec);