From 3a874ee7c0486405e4b74fb8019b7567b932dc69 Mon Sep 17 00:00:00 2001
From: Alex Marsev <alex.marsev@gmail.com>
Date: Wed, 27 Jan 2016 13:25:19 +0300
Subject: Replace DebugOut() helper function with macro

Ugly, but can't be helped. It's the only way to never evaluate the
arguments in release builds.
---
 src/Utils.h | 10 +++++++---
 1 file changed, 7 insertions(+), 3 deletions(-)

diff --git a/src/Utils.h b/src/Utils.h
index c2fa1fc..053eda3 100644
--- a/src/Utils.h
+++ b/src/Utils.h
@@ -99,9 +99,8 @@ namespace SaneAudioRenderer
     }
 
     template <typename... T>
-    inline void DebugOut(T&&... args)
+    inline void DebugOutBody(T&&... args)
     {
-        #ifndef NDEBUG
         try
         {
             std::wostringstream stream;
@@ -114,9 +113,14 @@ namespace SaneAudioRenderer
         {
             OutputDebugString(L"sanear: caught exception while formatting debug message");
         }
-        #endif
     }
 
+    #ifndef NDEBUG
+    #   define DebugOut(...) DebugOutBody(##__VA_ARGS__)
+    #else
+    #   define DebugOut(...)
+    #endif
+
     template <class T>
     inline const char* ClassName(T* p)
     {
-- 
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