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graph_spec.rb « network « models « spec - gitlab.com/gitlab-org/gitlab-foss.git - Unnamed repository; edit this file 'description' to name the repository.
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# frozen_string_literal: true

require 'spec_helper'

RSpec.describe Network::Graph do
  let(:project) { create(:project, :repository) }
  let!(:note_on_commit) { create(:note_on_commit, project: project) }

  describe '#initialize' do
    let(:graph) do
      described_class.new(project, 'refs/heads/master', project.repository.commit, nil)
    end

    it 'has initialized' do
      expect(graph).to be_a(described_class)
    end

    context 'when disable_network_graph_note_counts is disabled' do
      before do
        stub_feature_flags(disable_network_graph_notes_count: false)
      end

      it 'initializes the notes hash' do
        expect(graph.notes).to eq({ note_on_commit.commit_id => 1 })
      end
    end
  end

  describe '#commits' do
    let(:graph) { described_class.new(project, 'refs/heads/master', project.repository.commit, nil) }

    it 'returns a list of commits' do
      commits = graph.commits

      expect(commits).not_to be_empty
      expect(commits).to all(be_kind_of(Network::Commit))
    end

    it 'sorts commits by commit date (descending)' do
      # Remove duplicate timestamps because they make it harder to
      # assert that the commits are sorted as expected.
      commits = graph.commits.uniq(&:date)
      sorted_commits = commits.sort_by(&:date).reverse

      expect(commits).not_to be_empty
      expect(commits.map(&:id)).to eq(sorted_commits.map(&:id))
    end

    it 'sorts children before parents for commits with the same timestamp' do
      commits_by_time = graph.commits.group_by(&:date)

      commits_by_time.each do |time, commits|
        commit_ids = commits.map(&:id)

        commits.each_with_index do |commit, index|
          parent_indexes = commit.parent_ids.map { |parent_id| commit_ids.find_index(parent_id) }.compact

          # All parents of the current commit should appear after it
          expect(parent_indexes).to all(be > index)
        end
      end
    end
  end
end