*.[ch]: remove extern from function declarations using sed

There has been a push to remove extern from function declarations.
Finish the job by removing all instances of "extern" for function
declarations in headers using sed.

This was done by running the following on my system with sed 4.2.2:

    $ git ls-files \*.{c,h} |
        grep -v ^compat/ |
        xargs sed -i'' -e 's/^\(\s*\)extern \([^(]*([^*]\)/\1\2/'

Files under `compat/` are intentionally excluded as some are directly
copied from external sources and we should avoid churning them as much
as possible.

Then, leftover instances of extern were found by running

    $ git grep -w -C3 extern \*.{c,h}

and manually checking the output. No other instances were found.

Note that the regex used specifically excludes function variables which
_should_ be left as extern.

Not the most elegant way to do it but it gets the job done.

Signed-off-by: Denton Liu <liu.denton@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/quote.h b/quote.h
index 89f99e98fa..86c0d944b5 100644
--- a/quote.h
+++ b/quote.h
@@ -31,7 +31,7 @@ struct strbuf;
 
 void sq_quote_buf(struct strbuf *, const char *src);
 void sq_quote_argv(struct strbuf *, const char **argv);
-extern void sq_quotef(struct strbuf *, const char *fmt, ...);
+void sq_quotef(struct strbuf *, const char *fmt, ...);
 
 /*
  * These match their non-pretty variants, except that they avoid