*.[ch]: remove extern from function declarations using sed

There has been a push to remove extern from function declarations.
Finish the job by removing all instances of "extern" for function
declarations in headers using sed.

This was done by running the following on my system with sed 4.2.2:

    $ git ls-files \*.{c,h} |
        grep -v ^compat/ |
        xargs sed -i'' -e 's/^\(\s*\)extern \([^(]*([^*]\)/\1\2/'

Files under `compat/` are intentionally excluded as some are directly
copied from external sources and we should avoid churning them as much
as possible.

Then, leftover instances of extern were found by running

    $ git grep -w -C3 extern \*.{c,h}

and manually checking the output. No other instances were found.

Note that the regex used specifically excludes function variables which
_should_ be left as extern.

Not the most elegant way to do it but it gets the job done.

Signed-off-by: Denton Liu <liu.denton@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/worktree.h b/worktree.h
index ead36d6f54..2d6a1d207a 100644
--- a/worktree.h
+++ b/worktree.h
@@ -104,7 +104,7 @@ int is_worktree_being_bisected(const struct worktree *wt, const char *target);
  * Similar to git_path() but can produce paths for a specified
  * worktree instead of current one
  */
-extern const char *worktree_git_path(const struct worktree *wt,
+const char *worktree_git_path(const struct worktree *wt,
 				     const char *fmt, ...)
 	__attribute__((format (printf, 2, 3)));