Remove reference flag when ereferencing a pointer in a struct

This fixes the access of something like:

struct Foo {
  int bar[3];
}

struct Foo foo;
foo.bar[0] = 1;

2 files changed, 25 insertions, 0 deletions

diff --git a/ffi.c b/ffi.c
index 7fca4f9..a481b3c 100644
--- a/ffi.c
+++ b/ffi.c
@@ -1604,6 +1604,7 @@ static ptrdiff_t lookup_cdata_index(lua_State* L, int idx, int ct_usr, struct ct
         ct->is_array = 0;
         ct->pointers--;
         ct->const_mask >>= 1;
+        ct->is_reference = 0;
 
         lua_pushvalue(L, ct_usr);
 
diff --git a/test.lua b/test.lua
index ec37967..1393313 100644
--- a/test.lua
+++ b/test.lua
@@ -906,5 +906,29 @@ assert(ffi.istype('complex', sum))
 sum = ffi.C.add_fc(ffi.new('complex float', 1, 2), ffi.new('complex float', 3, 5))
 assert(ffi.istype('complex float', sum))
 
+ffi.cdef [[
+struct Arrays {
+    int ints[3];
+    unsigned int uints[3];
+};
+struct ArrayOfArrays {
+    struct Arrays arrays[3];
+};
+]]
+
+local struct = ffi.new('struct Arrays')
+local structOfStructs = ffi.new('struct ArrayOfArrays')
+for i=1,3 do
+    struct.ints[i] = i
+    struct.uints[i] = i
+    structOfStructs.arrays[0].ints[i] = i
+end
+for i=1,3 do
+    assert(struct.ints[i] == i)
+    assert(struct.uints[i] == i)
+    assert(structOfStructs.arrays[0].ints[i] == i)
+end
+
+
 print('Test PASSED')