Task scheduler: Remove counter of done tasks

This was only used for progress report, and it's wrong because:

- Pool might in theory be re-used by different tasks
- We should not make any decision based on scheduling stats

Proper way is to take care of progress by the task itself.

1 files changed, 0 insertions, 8 deletions

diff --git a/source/blender/blenlib/intern/task.c b/source/blender/blenlib/intern/task.c
index fc2d9674c2f..c4761e9f7ef 100644
--- a/source/blender/blenlib/intern/task.c
+++ b/source/blender/blenlib/intern/task.c
@@ -106,7 +106,6 @@ struct TaskPool {
 	TaskScheduler *scheduler;
 
 	volatile size_t num;
-	volatile size_t done;
 	size_t num_threads;
 	size_t currently_running_tasks;
 	ThreadMutex num_mutex;
@@ -238,7 +237,6 @@ static void task_pool_num_decrease(TaskPool *pool, size_t done)
 
 	pool->num -= done;
 	atomic_sub_and_fetch_z(&pool->currently_running_tasks, done);
-	pool->done += done;
 
 	if (pool->num == 0)
 		BLI_condition_notify_all(&pool->num_cond);
@@ -504,7 +502,6 @@ static TaskPool *task_pool_create_ex(TaskScheduler *scheduler, void *userdata, c
 
 	pool->scheduler = scheduler;
 	pool->num = 0;
-	pool->done = 0;
 	pool->num_threads = 0;
 	pool->currently_running_tasks = 0;
 	pool->do_cancel = false;
@@ -743,11 +740,6 @@ ThreadMutex *BLI_task_pool_user_mutex(TaskPool *pool)
 	return &pool->user_mutex;
 }
 
-size_t BLI_task_pool_tasks_done(TaskPool *pool)
-{
-	return pool->done;
-}
-
 /* Parallel range routines */
 
 /**